The oxidation state of Chromium (Cr) in the complex [Cr(H2O)4Cl2]+ is :
A
+5
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B
+3
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C
+7
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D
−5
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Solution
The correct option is B+3 The complex [Cr(H2O)4Cl2]+ has a overall charge +1 Let x be the oxidation state of Cr Since H2O is a neutral molecule, it has 0 overall charge. Charge on Cl=−1 x+(4×0)+(2×(−1))=+1x=+3