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Central Atom and Ligands

The oxidation...

Question

The oxidation state of $F e$ in Prussian blue is

A

+2

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B

+4

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C

+3

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D

0

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Solution

The correct option is C +3
Prussian blue is ferric ferrocyanide
i.e., $F e_{4} [F e (C N)_{6}]_{3}$

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Q. Prussian blue has two types of iron with oxidation number as shown below:

I I I F e [I I F e {(C N)}_{6}]

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