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Central Atom and Ligands

The oxidation...

Question

The oxidation state of $F e$ in Prussian blue is

A

2

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B

4

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C

3

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D

\N

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Solution

The correct option is C 3
Prussian blue is ferric ferrocyanide
i.e., $F e_{4} [F e (C N)_{6}]_{3}$

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