Question

The oxidation state of $I$ in $H_{4}I{O}_6^{-}$ is

• A. + 7
• B. + 5
• C. + 1
• D. - 1

Answer 1

The correct option is A + 7

Solution : Correct option is a).
$H_4\stackrel{\ast }{I}{O}_6^{-}$
$4+x-12=-1;x=-1+8=+7$