Question

The oxidation state of $I$ in $H_{4}I{O}_6^{-}$ is :

Answer 1

Let the oxidation state of $I$ in $H_{4}I{O}_6^{-}$ be $x$.
Since the overall charge on the complex is $-1$, the sum of oxidation states of all elements in it should be equal to $-1$.
Therefore, $4+x-12=-1$
or, $x=7$