The oxidation state of manganese in $K_{2} M n O_{4}$ is:

+ 5

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+ 6

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+ 4

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+ 7

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Solution

The correct option is B $+ 6$
Potassium oxidation number is $+ 1$ , Oxygen oxidation number is $- 2$ .
For $K_{2} M n O_{4}$ :
$2 (+ 1) +$ oxidation number of $M n + 4 (- 2) = 0$
$2 +$ Oxidation number of $M n - 8 = 0$
Oxidation number of $M n = + 6$ .
So answer is B.

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