Question

The oxidation state of nitrogen is correctly given for:

• A. $\begin{array}{cc}Compound& Oxidationstate\\ \left[CO{\left(N{H}_3\right)}_{5}Cl\right]{Cl}_2& 0\end{array}$
• B. $\begin{array}{cc}Compound& Oxidationstate\\ N{H}_{2}OH& -2\end{array}$
• C. $\begin{array}{cc}Compound& Oxidationstate\\ {\left(N_2{H}_5\right)}_{2}S{O}_4& +2\end{array}$
• D. $\begin{array}{cc}Compound& Oxidationstate\\ {Mg}_3{N}_2& -3\end{array}$

Answer 1

Answer: (D)

$\begin{array}{cc}Compound& Oxidationstate\\ {Mg}_3{N}_2& -3\end{array}$

a. ${\left[{Co}^{+3}\stackrel{0}{{\left(N{H}_3\right)}_5}{Cl}^{1-}\right]}^{+2}{Cl}_2^{-1\times 2}$
$N{H}_3:x+3=0\Rightarrow x=-3$; oxidation state of $N=-3$

b. $N{H}_{2}OH:x+3-2=0\Rightarrow x=-1$
Oxidation state of $N=-1$

c. ${\left(N_2{H}_5\right)}_2^{+1\times 2}S{O}_4^{2-}:N_2{H}_5^{\oplus }:2x+5=+1\Rightarrow x=-2$
Oxidation number of $N=-2$

d. $\stackrel{+2\times 3}{{Mg}_3}\stackrel{-3\times 2}{N_2}$: Oxidation state of $N=-3$