Question

The oxidation state of nitrogen is most positive in which of the following compounds?

• A. ${NO}_3^{-}$
• B. ${NO}_2^{-}$
• C. $N_{2}O$
• D. $N_2$
• E. ${NH}_3$

Answer 1

The correct option is A ${NO}_3^{-}$

${N{O}_3}^{-}:x+(3\times -2)=-1$

$\Rightarrow x-6=-1$

$\Rightarrow x=-1+6$

$\Rightarrow x=+5$.

${N{O}_2}^{-}:x+(2\times -2)=-1$

$\Rightarrow x=-1+4$

$\Rightarrow x=+3$

$N_{2}O:2x+(-2)=0$

$\Rightarrow 2x=2$

$\Rightarrow x=+1$

$N_2$: elemental state, so oxidation state is zero.

$N{H}_3:x+3=0$

$\Rightarrow x=-3$