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Question

The oxidation state of oxygen in KO3, Na2O2 are and respectively.

A
-0.33
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B
-1
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C
0.0
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D
-0.5
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Solution

The correct options are
A -0.33
B -1

We know that the sum of oxidation number of all the elements in a compound is equal to zero.
Using this information we can find the oxidation number of oxygen in both the compounds.
Let the oxidation number of oxygen in KO3 be x
So we can formulate the equation
KO3 +1+3×x=0

Hence, x=13
Let the oxidation number of oxygen in Na2O2 be y
So we can formulate the equation

Na2O2 +2+2×y=0
Hence, y=1

So the correct option is -0.33, -1


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