The oxidation state of oxygen in KO3, Na2O2 are
We know that the sum of oxidation number of all the elements in a compound is equal to zero.
Using this information we can find the oxidation number of oxygen in both the compounds.
Let the oxidation number of oxygen in KO3 be x
So we can formulate the equation
KO3⟹ +1+3×x=0
Hence, x=−13
Let the oxidation number of oxygen in Na2O2 be y
So we can formulate the equation
Na2O2⟹ +2+2×y=0
Hence, y=−1
So the correct option is -0.33, -1