The oxidation state of S-atom is $- 1$ in :

F e S

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F e S_{2}

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N a O - O | | S | | O - O N a

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N a O - O | | S - O | | S - O N a

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Solution

The correct option is B $F e S_{2}$
(a) $F e S$ oxidation state of S = +2

(b)In $F e S_{2}$ iron is in +2 state. $F e S_{2}$ contains the $S_{2}^{2 -}$ ion, which is analogous to the peroxide ion, $O_{2}^{2 -}$ . The oxidation state of sulphur is -1 in $F e S_{2}$ , just as oxygen is in peroxides like $H_{2} O_{2}$ and $B a O_{2}$ .

(c)oxidation state of S = +6

(d)oxidation state of S = +3

Hence,option B is correct.

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