The oxidation states of S atoms in $S_{4} O_{6}^{2 -}$ from left to right respectively, are:
$O - O | | S | | O - S - S - O | | S | | O - O^{-}$

+6,0,0,+6

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+3,1,+1,+3

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+5,0,0,+5

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None of above

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Solution

The correct option is C +5,0,0,+5
The oxidation state of sulphur is $n - 2 - 2 - 1 + 0 = 0; n = 5$
So, the oxidation state of sulphur is $+ 5$ isolated $S - S$ linkage have zero oxidation state.
$\Rightarrow + 5, 0, 0, + 5 =$ Oxidation state.

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