The oxidation states of sulphur in the anions SO 32- S 2 O 42- and S 2 O 62- and follows the order-A- SO 32- S 2 O 42- S 2 O 62-B- S 2 O 42- SO 32- S 2 O 62C- S 2 O 42- S 2 O 62- SO 32-D- S 2 O 62- S 2 O 42- SO 32

The correct option is B S_2O_4^2 lt; SO_3^2 lt; S_2O_6^2 S in S_2O_4^2 , SO_3^2 and S_2O_6^2 has +3, +4 and +5 oxidation number. ...

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Catalytic Hydrogenation

The oxidation...

Question

The oxidation states of sulphur in the anions $S O_{3}^{2 -}, S_{2} O_{4}^{2 -} a n d S_{2} O_{6}^{2 -}$ and follows the order:

S_{2} O_{4}^{2 -} < S O_{3}^{2 -} < S_{2} O_{6}^{2 -}

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S O_{3}^{2 -} < S_{2} O_{4}^{2 -} < S_{2} O_{6}^{2 -}

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S_{2} O_{4}^{2 -} < S_{2} O_{6}^{2 -} < S O_{3}^{2 -}

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S_{2} O_{6}^{2 -} < S_{2} O_{4}^{2 -} < S O_{3}^{2 -}

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S O_{3}^{2 -}, S_{2} O_{4}^{2 -}

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