The oxidation states of sulphur in the anions $S O_{3}^{2 -}, S_{2} O_{4}^{2 -}$ and $S_{2} O_{6}^{2 -}$ follow the order

S_{2} O_{6}^{2 -} < S_{2} O_{4}^{2 -} < S O_{3}^{2 -}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

S_{2} O_{4}^{2 -} < S O_{3}^{2 -} < S_{2} O_{6}^{2 -}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

S O_{3}^{2 -} < S_{2} O_{4}^{2 -} < S_{2} O_{6}^{2 -}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

S_{2} O_{4}^{2} < S_{2} O_{6}^{2 -} < S O_{3}^{2 -}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $S_{2} O_{4}^{2 -} < S O_{3}^{2 -} < S_{2} O_{6}^{2 -}$
Solution: Correct option is b).
$S_{2} O_{4}^{2 -} < S O_{4}^{2 -} < S_{2} O_{6}^{2 -}$

Oxi. state of sulphur in $S_{2} O_{4}^{2 -} = + 3$
Oxi. state of sulphur in $S O_{3}^{2 -} = + 4$
Oxi state of sulphur in $S_{2} O_{6}^{2 -} . = + 5$

Suggest Corrections

Similar questions

S O_{3}^{2 -}

S_{2} O_{4}^{2 -}

S_{2} O_{6}^{2 -}

S O_{3}^{2 -}, S_{2} O_{4}^{2 -} a n d S_{2} O_{6}^{2 -}

S O_{3}^{2 -}, S_{2} O_{4}^{2 -}

S_{2} O_{6}^{2 -}

S O_{3}^{2 -}, S_{2} O_{4}^{2 -}

S_{2} O_{6}^{2 -}

{S O}_{3}^{2 -}, {S O}_{4}^{2 -}, S_{2} O_{4}^{2 -}, S_{2} O_{6}^{2 -}

Join BYJU'S Learning Program