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Question

The oxidation states of sulphur in the anions SO2−3,S2O2−4 and S2O2−6 and follows the order:

A
S2O24<SO23<S2O26
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B
SO23<S2O24<S2O26
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C
S2O24<S2O26<SO23
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D
S2O26<S2O24<SO23
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Solution

The correct option is A S2O24<SO23<S2O26
S in S2O24,SO23 and S2O26 has +3, +4 and +5 oxidation number.

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