The oxidation states of the two types of sulphur atoms in $N a_{2} S_{4} O_{6}$ is

+6, +4

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+5, 0

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+6, 0

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+6, -2

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Solution

The correct option is B +5, 0

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Similar questions

N a_{2} S_{4} O_{6}

N a_{2} S_{4} O_{6}

The oxidation state of S atom in $[H S O_{4}]^{-}$ is

N a_{2} S_{4} O_{6}

N a_{2} S_{4} O_{6}

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