The oxide of a metal has 32% oxygen. Its equivalent weight would be :

34

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32

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17

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16

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Solution

The correct option is C $17$
Let the metal oxide be $100 g$ .

Weight of oxygen will be $32 g$ .

$W_{O_{2}} = 32 g$

So, the weight of metal will be $68 g$ .

$W_{M} = 68 g$

$E_{W} = \frac{W_{M} \times 8}{W_{O_{2}}} = \frac{68 \times 8}{32}$

Now, Equivalent weight $E_{W} = \frac{w e i g h t o f o x i d e}{w e i g h t o f O_{2}} \times 8 = \frac{W_{M} \times 8}{W_{O_{2}}} = \frac{68 \times 8}{32}$

$E_{W} = 544 / 32 = 17$

So the equivalent weight of oxide $= 17$ .

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The oxide of a metal has 32% oxygen. Its equivalent weight would be :

The correct option is C 17Let the metal oxide be 100g.Weight of oxygen will be 32g.WO2=32gSo, the weight of metal will be 68g.WM=68gEW=WM×8WO2=68×832Now, Equivalent weight EW=weight of oxideweight of O2×8=WM×8WO2=68×832EW=544/32=17So the equivalent weight of oxide =17.