Question 7

The oxide that gives $H_{2} O_{2}$ on treatment with dilute $H_{2} S O_{4}$ is

(a) $P b O_{2}$ (b) $B a O_{2} .8 H_{2} O + P_{2}$

(c) $M n O_{2}$ (d) $T i O_{2}$

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Solution

(b)

Oxides such as $B a O_{2}, N a_{2} O_{2}$ etc ; which contain peroxide linkage (i.e., -O-O or $O_{2}^{2 -})$ on treatment with dilute $H_{2} S O_{4}$ give $H_{2} O_{2}$ but dioxides (O=M=O, where M is the metal atom) such as $P b O_{2}, M n O_{2}, T i O_{2}$ do not give $H_{2} O_{2}$ on treatment with dilute $H_{2} S O_{4}$ .

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Similar questions

H_{2} O_{2}

The oxide that gives hydrogen peroxide ( $H_{2} O_{2}$ ) on the treatment with a dilute acid ( $H_{2} S O_{4}$ ) is

H_{2} O_{2}

H_{2} S O_{4}

H_{2} O_{2}

H_{2} O_{2}

H_{2} S O_{4}

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