The oxide that gives hydrogen peroxide ( $H_{2} O_{2}$ ) on the treatment with a dilute acid ( $H_{2} S O_{4}$ ) is

MnO₂

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PbO₂

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Na₂O₂

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TiO₂

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Solution

The correct option is C
Na₂O₂

$N a_{2} O_{2}$ + $H_{2} S O_{4}$ $\to$ $N a_{2} S O_{4}$ + $H_{2} O_{2}$

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H_{2} O_{2}

Question 7

The oxide that gives $H_{2} O_{2}$ on treatment with dilute $H_{2} S O_{4}$ is

(a) $P b O_{2}$ (b) $B a O_{2} .8 H_{2} O + P_{2}$

(H_{2} O_{2})

(H_{2} {S O}_{4})

H_{2} O_{2}

H_{2} S O_{4}

H_{2} O_{2}

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