Question

The oxidizing agent for the reaction below is:
$Al+Mn{O}_4^{-}\to Al{\left(OH\right)}_4^{-}+Mn{O}_2$

• A. $A{l}^{3+}$
• B. $Al$
• C. $Mn{O}_4^{-}$
• D. $Mn{O}_2$

Answer 1

The correct option is C $Mn{O}_4^{-}$

$Al+\stackrel{+7}{Mn{O}_4^{-}}⟶Al(OH{)}_4^{-}+\stackrel{+4}{Mn{O}_2}$

$\downarrow$ $\uparrow$

{Decrease in Oxidation state : Reduction}

$\because$ It is reduction so it acts as Oxidising agent.