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Question

The PV diagram of a system undergoing thermodynamic transformation is shown in figure. The work done by the system and heat given to the system in going from ABC is 30 J and 40 J respectively. The change in internal energy between A and C is


A
70 J
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B
10 J
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C
70 J
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D
10 J
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Solution

The correct option is B 10 J
Given,

WAB+WBC=30 J
QAB+QBC=40 J
Applying 1st law of thermodynamics for process AB,
QAB=ΔUAB+WAB(1)
Simillarly applying 1st law of thermodynamics for process BC,
QBC=ΔUBC+WBC(2)
Adding (1) and (2),
QAB+QBC=ΔUAB+WAB+ΔUBC+WBC
40=(ΔUAB+ΔUBC)+30
Here ΔUAB+ΔUBC=ΔUAC
ΔUAC=4030=10 J

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