The pair of boiling point and compound are given as,
$C_{6} H_{6},$ $C H_{3} O H$ $C_{6} H_{5} N O_{2}$ $C_{6} H_{5} N H_{2}$
$80^{o} C$ $65^{o} C$ $212^{o} C$ $184^{o} C$
(I) (II) (III) (IV)
Which will show lowest vapour pressure at room temperature?

C_{6} H_{6}

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C H_{3} O H

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C_{6} H_{5} N O_{2}

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C_{6} H_{5} N H_{2}

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Solution

The correct option is C $C_{6} H_{5} N O_{2}$
As the boiling point is inversely proportional to vapour pressure hence, nitrobenzene having bp $212^{o} C$ will show the lowest vapour pressure at room temperature.

This is because low vapour pressure makes the substance more non-volatile and thus increase its boiling point.

Option C is correct.

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The boiling point of C6H6 , CH3OH , C6H5NH2 and C6H5NO2 are 800C , 650C , 1840C and 2120C respectively. Which will show highest vapour pressure at room temperature?

Q. The boiling point of

C_{6} H_{6}, C H_{3} O H, C_{6} H_{5} N H_{2}

and

C_{6} H_{5} N O_{2}

are

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respectively. Which will show highest vapourr pressure at room temperature?

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and

C_{6} H_{5} N O_{2}

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212^{0} C

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The pair of boiling point and compound are given as, C6H6, CH3OH C6H5NO2 C6H5NH2 80oC 65oC 212oC 184oC (I) (II) (III) (IV)Which will show lowest vapour pressure at room temperature?

The pair of boiling point and compound are given as,
$C_{6} H_{6},$ $C H_{3} O H$ $C_{6} H_{5} N O_{2}$ $C_{6} H_{5} N H_{2}$
$80^{o} C$ $65^{o} C$ $212^{o} C$ $184^{o} C$
(I) (II) (III) (IV)
Which will show lowest vapour pressure at room temperature?