The pair of compounds having identical shapes for their molecules is :

B {C l}_{2}, C l F_{3}

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S O_{2}, C O_{2}

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C H_{4}, S F_{4}

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X e F_{2}, Z n {C l}_{2}

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Solution

The correct option is C $B {C l}_{2}, C l F_{3}$
$B C l_{2}$ has bent shape with one unpaired electron and $C l F_{3}$ also have bent shape with $2$ lone pairs.

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