The pair of equations $3 x + 5 y = 3$ and $6 x + k y = 8$ have no solution if $k =$

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Solution

The correct option is A 10
The equation are
$3 x + 5 y - 3 = 0$
$6 x + k y - 8 = 0$
Here, $a_{1} = 3, b_{1} = 5, c_{1} = - 3$
and $a_{2} = 6, b_{2} = k, c_{2} = - 8$
Given, the system of equation has no solution
$\Rightarrow \frac{a_{1}}{a_{2}} = \frac{b_{1}}{b_{2}} \neq \frac{c_{1}}{c_{2}}$
$\Rightarrow \frac{3}{6} = \frac{5}{k} \neq \frac{- 3}{- 8}$
$\Rightarrow k = 10$

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