Question

The pair of linear equations $2x-3y=1$ and $3x-2y=4$ have:

• A. One solution
• B. Two solutions
• C. No solution
• D. Many solutions

Answer 1

The correct option is A One solution

For the given pair of equations $2x-3y=1$ and $3x-2y=4$;

$\frac{a_1}{a_2}=\frac{2}{3}$

$\frac{b_1}{b_2}=\frac{-3}{-2}=\frac{3}{2}$

$\frac{c_1}{c_2}=\frac{-1}{-4}=\frac{1}{4}$

As the given pair of linear equations satisfies -

$\frac{a_1}{a_2}\ne \frac{b_1}{b_2}$

The graph will be a pair of lines intersecting at a unique point, which is the solution of the pair of equations.