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Question

The pairs of linear equations which have the unique solution x = 2, y = –3 are


A

x + y = –1 ; 2x – 3y = –5

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B

2x + 5y = –11 ; 4x + 10y = –22

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C

2x – y = 1 ; 3x + 2y = 0

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D

x – 4y –14 = 0 ; 5x – y – 13 = 0

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Solution

The correct options are
A

x + y = –1 ; 2x – 3y = –5


D

x – 4y –14 = 0 ; 5x – y – 13 = 0


Option A:

x + y = –1

2x + 3y = –5

Solving by elimination we get x = 2 and y = -3.

Option D:

x - 4y = 14

5x - y = 13

Using cross multiplication method and solve

We get,

x = 2 and y = -3


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