The pairs of linear equations which have the unique solution x = 2, y = –3 are
x + y = –1 ; 2x – 3y = –5
x – 4y –14 = 0 ; 5x – y – 13 = 0
Option A:
x + y = –1
2x + 3y = –5
Solving by elimination we get x = 2 and y = -3.
Option D:
x - 4y = 14
5x - y = 13
Using cross multiplication method and solve
We get,
x = 2 and y = -3