The partial pressure of ethane over a saturated solution containing 6-56- 10-2 g of ethane is 1 bar- If the solution contains 5- 10-2 g of ethane- then what will be the partial pressure of the gas-

S_1S_2=P_1P_2 6.56× 10^ 25× 10^ 2=1P_2 P_2=0.762 bar ...

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Byju's Answer

Standard XII

Chemistry

Dalton's Law of Partial Pressures

The partial p...

Question

The partial pressure of ethane over a saturated solution containing $6.56 \times 10^{- 2} g$ of ethane is 1 bar. If the solution contains $5 \times 10^{- 2} g$ of ethane, then what will be the partial pressure of the gas?

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Solution

$\frac{S_{1}}{S_{2}} = \frac{P_{1}}{P_{2}}$
$\frac{6.56 \times 10^{- 2}}{5 \times 10^{- 2}} = \frac{1}{P_{2}}$
$P_{2} = 0.762 b a r$

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The partial pressure of ethane over a saturated solution containing 6.56×10−2g of ethane is 1 bar. If the solution contains 5×10−2g of ethane, then what will be the partial pressure of the gas?

S1S2=P1P26.56×10−25×10−2=1P2P2=0.762bar

The partial pressure of ethane over a saturated solution containing $6.56 \times 10^{- 2} g$ of ethane is 1 bar. If the solution contains $5 \times 10^{- 2} g$ of ethane, then what will be the partial pressure of the gas?

$\frac{S_{1}}{S_{2}} = \frac{P_{1}}{P_{2}}$
$\frac{6.56 \times 10^{- 2}}{5 \times 10^{- 2}} = \frac{1}{P_{2}}$
$P_{2} = 0.762 b a r$