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Question

The partial pressure of ethane over a saturated solution containing 6.56×102 g of ethane in water is 1 bar. If the solution contains 5×102 g of ethane, then what shall be the partial pressure of the gas ?

Assume: nH2O>>nethane

A
0.2 bar
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B
1.55 bar
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C
0.76 bar
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D
2 bar
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Solution

The correct option is C 0.76 bar
According to Henry's Law
Pgas=KH×χgas

Case 1:
1=KH×nethanenethane+nH2O

Since, nH2O>>nethane

1=KH×nethanenH2O1=KH×6.56×10230nH2O

1=KH×6.56×10230×nH2O eqn(i)

Case 2:
Pgas=KH×nethanenethane+nH2O

Since, nH2O>>nethane

Pgas=KH×nethanenH2OPgas=KH×5×10230nH2O

Pgas=KH×5×10230×nH2O eqn(ii)

Dividing eqn(ii) by eqn(i)
Pgas1=KHKH×5×102×nH2O×306.56×102×nH2O×30Pgas=56.56=0.76 bar

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