Question

The partial pressure of ethane over a solution containing $6.56\times {10}^{-3}g$ of ethane is $1$ bar. If the solution contains $5.00\times {10}^{-2}g$ of ethane, then what shall be the partial pressure of the gas?

Answer 1

According to Henry's law, the solubility of gas in a liquid is directly proportional to the pressure of the gas.
$X=K_h\times P$
$X$ is the mole fraction of gas, $K_h$ is the Henry's law constant and $P$ is the partial pressure of the gas.
Also mole fraction of ethane will be directly proportional to its mass.
$W{P}^{\prime }=W^{\prime }P$
$W$ is the mass of ethane in first solution and $P$ is the partial pressure of ethane in first solution.
$W^{\prime }$ is the mass of ethane in second solution and $P^{\prime }$ is the partial pressure of ethane in second solution.
$6.56\times {10}^{-3}\times P^{\prime }=5.00\times {10}^{-2}\times 1P^{\prime }=7.6$
Hence, the partial pressure of gas will be 7.6 bar.