The particle executing simple harmonic motion has a kinetic energy K0cos2 - t- The maximum values of the potential energy and the total energy are respectively

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Wave Equation

The particle ...

Question

The particle executing simple harmonic motion has a kinetic energy $K_{0} c o s^{2} ω t$ . The maximum values of the potential energy and the total energy are respectively

K_{0}

and

K_{0}

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0

and

2 K_{0}

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\frac{K_{0}}{2}

and

K_{0}

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K_{0}

and

2 K_{0}

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Solution

The correct option is A $K_{0}$ and $K_{0}$
KE= $K_{0} c o s^{2} ω t$
Therefore $K E_{m a x} = K_{0}$
When potential energy is maximum at extreme points Kinetic energy is 0
Therefore due to conservation of energy $P E_{m a x} = K_{0}$
At extreme point $P E = K_{0}$ and KE=0 and total energy= $K_{0}$

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