Question

The particle is executing $S.H.M.$ on a line $4cm$ long. If its velocity at mean position is $12cm/sec$, its frequency in $Hz$ will be :

• A. $\frac{2\pi }{3}$
• B. $\frac{3}{2\pi }$
• C. $\frac{\pi }{3}$
• D. $\frac{3}{\pi }$

Answer 1

The correct option is D $\frac{3}{\pi }$

Amplitude$=2cm=A$

Velocity of SHM at mean position

$=A\omega$

$\Rightarrow 12=A\omega$

$12=2\times \omega \Rightarrow \omega =6$

Frequency $=\frac{\omega }{2\pi }$

$\Rightarrow f=\frac{6}{2\pi }=\frac{3}{\pi }$

$\Rightarrow f=\frac{3}{\pi }$

Option D.