Question

The particle $X$ in the following nuclear reaction is ${}_3^{7}Li$ + ${}_1^1\text{H}$ $⟶$ ${}_2^4\text{He}$ + $X$

• A. $a$
• B. $n$
• C. $e$
• D. $p$

Answer 1

The correct option is A $a$

Mass number of $Li$ is $7$.

So $X$ should have a mass number of $4$ and atomic number of $2$.

$X$ is a $\alpha$ particle.