Question

The path A→B→C→D→E→F→G→H is a bus route plotted on a map. If the coordinates of the points are as given, find the difference between the length of the bus route and the shortest distance from A to H.

A	B	C	D	E	F	G	H
(2,5)	(2,2)	(8,2)	(8,5)	(6,5)	(6,4)	(4,4)	(2,5)

• A. 20 units
• B. 18 units
• C. 16 units
• D. 14 units

Answer 1

The correct option is C 16 units

Plotting the bus route, we find:


Now, measuring the length of each section of the route, we get:


Now, the total length of the route can be calculated as:

$TotalLength=3+6+3+2+1+2+1$
$=18units$

Next, we find the shortest distance from A to H.


Hence, the shortest distance from A to H is 2 units.

Therefore the difference between the length of the bus route and the shortest distance is:

$18units-2units=16units$