Question

The pd across a resistor of resistance 10 $\Omega$, if ${10}^{20}$ electrons flow through it in one second is _____ V

• A. 160 V
• B. 120 V
• C. 410 V
• D. 31 V

Answer 1

The correct option is A 160 V

$Q=Ne$ where $N=$ number of electrons

$I=\frac{Q}{t}=\frac{Ne}{t}=\frac{{10}^{20}\times 1.6\times {10}^{-19}}{1}=16A$

pd$=V=IR=16\times 10$

$⟹V=160V$

Answer-(A)