Question

The peak power consumed by a resistive coil when connected to an AC source is 80 W. Find the enrgy consumed by the coil in 100 seconds which many times larger than the time period of the source.

Answer 1

Here P_0 = 80 W

$P_{rms}=\frac{P_0}{2}$= 40 W

Energy consumed = P $\times$ t

= 40 $\times$ 100

= 4000 J = 4.0 KJ