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Question

The peak power consumed by a resistive coil, when connected to an AC source, is 80 W. Find the energy consumed by the coil in 100 seconds, which is many times larger than the time period of the source.

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Solution

Peak power of the resistive coil, P0 =80 W
Time, t = 100 s
RMS value of power Prms is given by,
Prms = P02,
where P0 = Peak value of power
Prms=P02=40 W
Energy consumed E is given by,
E = Prms × t
= 40 × 100
= 4000 J = 4.0 kJ

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