The peak value of an alternating emf is given by E=E0cos(wt) is 10 volt and its frequency is 50 Hz. At a time t=(1600) second, the instantaneous value of the emf is:
A
1V
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B
5V
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C
5√3V
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D
10V
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Solution
The correct option is C5√3V E = E0 Cos wt = 10 cos [2 πnt] =10cos[2×π×50×1600] = 10 cos (π6) =10×√32=5√3V