The peak voltage of 220 Volt AC mains (in Volt) is :

155.6

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220

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311

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440

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Solution

The correct option is C 311
Peak voltage = $V_{R m s} \times \sqrt{2}$
$= 220 \times \sqrt{2}$
$= 311 V$ .

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The peak voltage of 220 Volt AC mains (in Volt) is :

The correct option is C 311Peak voltage = VRms×√2 =220×√2 =311V.

The correct option is C 311
Peak voltage = $V_{R m s} \times \sqrt{2}$
$= 220 \times \sqrt{2}$
$= 311 V$ .