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Price Elasticity of Supply

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Question

The percentage by volume of $C_{3} H_{8}$ in a mixture of $C_{3} H_{8}$ , $C H_{4}$ and CO is 36.5. Calculate the volume of $C O_{2}$ produced when 100 mL of mixture is burnt in excess of $O_{2}$ .

A

170 ml

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B

173 ml

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C

180 ml

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D

183 ml

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Solution

The correct option is B
173 ml

When the mixture is burnt, all the 3 components will burn. So,
$C_{3} H_{8}$ + 5 $O_{2}$ → 3 $C O_{2}$ + 4 $H_{2}$ O(l)
C $H_{4}$ + 2 $O_{2}$ → $C O_{2}$ + 2 $H_{2}$ O(l)
2CO + 2 $O_{2}$ → 2 $C O_{2}$
If I take 100 ml sample of the mixture having a ml of $C_{3} H_{8}$ , b ml of C $H_{4}$ and c ml of CO,
a = 36.5 ml
a + b + c = 100 ml
from the reactions and Avagadro's Law,
1 unit vol $C_{3} H_{8}$ gives 3 unit vol $C O_{2}$
1 unit vol C $H_{4}$ gives 1 unit vol $C O_{2}$
And1 vol CO gives 1 vol $C O_{2}$
∴ Total volume of $C O_{2}$ obtained = 3(a) + 1(b) + 1(c)
= 3(36.5) + (b + c)
= 3(36.5) + (100 - 36.5) =173 ml

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