CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The percentage by volume of C3H8 in a mixture of C3H8, CH4 and CO is 36.5. Calculate the volume of CO2 produced when 100 mL of mixture is burnt in excess of O2.


A

170 ml

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

173 ml

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C

180 ml

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

183 ml

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B

173 ml


When the mixture is burnt, all the 3 components will burn. So,
C3H8 + 5 O2 → 3CO2 + 4H2O(l)
CH4 + 2O2CO2+ 2H2O(l)
2CO + 2O2→ 2CO2
If I take 100 ml sample of the mixture having a ml of C3H8, b ml of CH4 and c ml of CO,
a = 36.5 ml
a + b + c = 100 ml
from the reactions and Avagadro's Law,
1 unit vol C3H8 gives 3 unit vol CO2
1 unit vol CH4 gives 1 unit vol CO2
And1 vol CO gives 1 vol CO2
∴ Total volume of CO2 obtained = 3(a) + 1(b) + 1(c)
= 3(36.5) + (b + c)
= 3(36.5) + (100 - 36.5) =173 ml


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Elasticity of Supply
ECONOMICS
Watch in App
Join BYJU'S Learning Program
CrossIcon