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Normal Reaction

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Question

The percentage of "fayalite" in an "OLIVINE" with density $3.88$ g cm $^{- 3}$ is:

A

75 %

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B

59 %

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C

35 %

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D

29 %

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Solution

The correct option is B $59 %$
The percentage of "fayalite" in an "OLIVINE" be $x$ . The percentage of forsterite will be $100 - x$

The density of "OLIVINE", "fayalite" and forsterite are $3.88$ g/ml, $4.34$ g/mol and $3.21$ g/ml respectively :
$100 \times 3.88 = 4.34 x + 3.21 (100 - x)$
$388 = 4.34 x + 321 - 3.21 x$
$67 = 1.13 x$
$x = 59$ %

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