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Question
The percentage of hydrolysis in 0.003 M aqueous solution of NaOCN is:
(Ka for HOCN = 3.33 × 10−4 M)
The percentage of hydrolysis in 0.003 M aqueous solution of NaOCN is:
(Ka for HOCN = 3.33 × 10−4 M)
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Solution
The correct option is A 0.01 %
The concerned chemical reaction is
OCN− + H2O ↔ HOCN + OH−
The reaction in question involves the hydrolysis of a salt of strong base and weak acid.
h2 = KwcKa = 10−8
h = 10−4
= 10−2%
0.01 %
The concerned chemical reaction is
OCN− + H2O ↔ HOCN + OH−
The reaction in question involves the hydrolysis of a salt of strong base and weak acid.
h2 = KwcKa = 10−8
h = 10−4
= 10−2%
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