The percentage of nitrogen in aluminium nitride is :
[ $A l = 27, N = 14$ ]

34.15 %

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14.15 %

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24.30 %

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38.15 %

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Solution

The correct option is A $34.15 %$
Molar mass of $A l N = 41$ gm
% $N$ $= 14 \times \frac{100}{41} = 34.15$

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