The percentage of nitrogen in urea is about :

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Solution

The correct option is C 47
Urea is $N H_{2} C O N H_{2}$
% of N = $28 * 100 / 60 = 47$ %

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Calculate the percentage of nitrogen in Urea.

(N H_{2} C O N H_{2})

H_{2} N C O N H_{2}

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