The perimeter of a rectangle is $40 c m$ . The length of rectangle is more than double its breadth by $2 c m$ . Find the length and breadth of rectangle .

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Solution

Perimeter of rectangle $= 40$ cm (given)

condition :- length = $2 \times$ breadth $+ 2$
$\Rightarrow l = 2 b + 2$

perimeter $p = 2 (l + b) = 40$
$\Rightarrow 2 (2 b + 2 + b) = 40$
$\Rightarrow 2 (3 b + 2) = 40$
$\Rightarrow 6 b = 40 - 4 = 36$
$∴ b = 6 c m$

$l = 2 \times 6 + 2 = 12 + 2 = 14 c m$

$∴$ length $= 14$ cm, breadth $= 6$ cm

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The perimeter of a rectangle is 40 cm. The length of rectangle is more than double its breadth by 2 cm. Find the length and breadth of rectangle .

Perimeter of rectangle =40 cm (given)condition :- length = 2× breadth +2⇒l=2b+2perimeter p=2(l+b)=40⇒2(2b+2+b)=40⇒2(3b+2)=40⇒6b=40−4=36∴b=6cml=2×6+2=12+2=14cm∴ length =14 cm, breadth =6 cm

The perimeter of a rectangle is $40 c m$ . The length of rectangle is more than double its breadth by $2 c m$ . Find the length and breadth of rectangle .