Question

The perimeter of a rectangle is $46m$ and its length is $15m.$ Find its:

(i) breadth (ii) area (iii) diagonal.

Answer 1

Given: Perimeter of rectangle $=46m$

Length, $l=15m$

We know that the perimeter of rectangle is given by $2(length+breadth)$

$\therefore 2(l+b)=46$

$\Rightarrow 2(15+b)=46$

$\Rightarrow 15+b=\frac{46}{2}$

$\Rightarrow b=23-15$

$\Rightarrow b=8m$

(ii) Area of the rectangle $=l\times b=15\times 8=120m^2$

(iii) Diagonal of rectangle $=\sqrt{l^2+b^2}=\sqrt{{15}^2+8^2}$

$=\sqrt{225+64}=\sqrt{289}=\sqrt{17\times 17}=17m$