The perimeter of a rectangle of $l e n g t h = 20 c m$ and $w i d t h = 12 c m$ is , while its area is .

64 c m

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240 c m^{2}

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240 c m

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64 c m^{2}

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Solution

The correct option is B $240 c m^{2}$
Given sides as length $l = 20 c m$ and width $w = 12 c m$
We know perimeter of a rectangle $= 2 \times (l + w)$
$= 2 \times (20 + 12)$
$= 2 \times 32$
$= 64 c m$
Similarly area of a rectangle is the product of side lengths
$= l \times w = 20 \times 12$
$= 320 c m^{2}$

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The perimeter of a rectangle of length=20 cm and width=12 cm is , while its area is .

The correct option is B 240 cm2Given sides as length l=20 cm and width w=12 cm We know perimeter of a rectangle =2×(l+w) =2×(20+12) =2×32 =64 cm Similarly area of a rectangle is the product of side lengths =l×w=20×12 =320 cm2

The perimeter of a rectangle of $l e n g t h = 20 c m$ and $w i d t h = 12 c m$ is , while its area is .