The perimeter of a right angled triangle is 160cm and its sides are in the ratio 8:15:17. Then find its hypotenuse.

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Solution

Sides are inthe ratio 8:15:17.
so we takes sides as 8x,15x,17x
perimeter=sum of all sides=8x+15x+17x
=40x
given perimeter=160
so 160=40x
160/40=x
4=x
so sides are 84,154,17*4
32,60,68
For a right traingle hypotenise is largest side
so hypotenuse is 68 units

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The perimeter of a right angled triangle is 160cm and its sides are in the ratio 8:15:17. Then find its hypotenuse.

Sides are inthe ratio 8:15:17. so we takes sides as 8x,15x,17x perimeter=sum of all sides=8x+15x+17x =40x given perimeter=160 so 160=40x 160/40=x 4=x so sides are 8*4,15*4,17*4 32,60,68 For a right traingle hypotenise is largest side so hypotenuse is 68 units

Sides are inthe ratio 8:15:17.
so we takes sides as 8x,15x,17x
perimeter=sum of all sides=8x+15x+17x
=40x
given perimeter=160
so 160=40x
160/40=x
4=x
so sides are 84,154,17*4
32,60,68
For a right traingle hypotenise is largest side
so hypotenuse is 68 units