The perimeter of a triangle is $15 x^{2} - 23 x + 9$ and two of its sides are $5 x^{2} + 8 x - 1$ and $6 x^{2} - 9 x + 4$ . Find the third side

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Solution

Formula For Perimeter of triangle = $(s i d e)_{1} + (s i d e)_{2} + (s i d e)_{3}$
Using formula We have :-
$(15 x^{2} - 23 x + 9)$ = $5 x^{2} + 8 x - 1 + 6 x^{2} - 9 x + 4 + (s i d e)_{3}$
$\Rightarrow$ $(15 x^{2} - 23 x + 9)$ = $11 x^{2} - x + 3 + (s i d e)_{3}$
$\Rightarrow$ $(s i d e)_{3} = 15 x^{2} - 23 x + 9 - 11 x^{2} + x - 3$
$\Rightarrow$ $(s i d e)_{3}$ = $4 x^{2} - 22 x + 6$
The answer is $4 x^{2} - 22 x + 6$

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The perimeter of a triangle is 15x2−23x+9 and two of its sides are 5x2+8x−1 and 6x2−9x+4. Find the third side

Formula For Perimeter of triangle = (side)1+(side)2+(side)3 Using formula We have :- (15x2−23x+9) = 5x2+8x−1+6x2−9x+4+(side)3 ⇒ (15x2−23x+9)= 11x2−x+3+(side)3 ⇒ (side)3=15x2−23x+9−11x2+x−3 ⇒ (side)3 = 4x2−22x+6 The answer is 4x2−22x+6

The perimeter of a triangle is $15 x^{2} - 23 x + 9$ and two of its sides are $5 x^{2} + 8 x - 1$ and $6 x^{2} - 9 x + 4$ . Find the third side