The perimeter of two similar triangles are $24$ cm and $16$ cm, respectively. If one side of the first triangle is $10$ cm, then the corresponding side of the second triangle is

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\frac{20}{3}

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\frac{16}{3}

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Solution

The correct option is B $\frac{20}{3}$ cm
In similar triangles, ratio of the sides is equal to the ratio of the perimeters.
Thus, $\frac{p_{1}}{p_{2}} = \frac{s_{1}}{s_{2}}$
$\frac{24}{16} = \frac{10}{s_{2}}$
$s_{2} = \frac{20}{3}$
Thus, side of the other triangle is $\frac{20}{3}$ cm.

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The perimeter of two similar triangles are 24 cm and 16 cm, respectively. If one side of the first triangle is 10 cm, then the corresponding side of the second triangle is

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The correct option is B $\frac{20}{3}$ cm
In similar triangles, ratio of the sides is equal to the ratio of the perimeters.
Thus, $\frac{p_{1}}{p_{2}} = \frac{s_{1}}{s_{2}}$
$\frac{24}{16} = \frac{10}{s_{2}}$
$s_{2} = \frac{20}{3}$
Thus, side of the other triangle is $\frac{20}{3}$ cm.