Question

The perimeters of two similar triangles ABC and LMN are 60 cm and 48 cm respectively If LM=8 cm, the length of AB is

• A. $10cm$
• B. $8cm$
• C. $6cm$
• D. $4cm$

Answer 1

The correct option is A $10cm$

If two triangles are similar then the ratio of their perimeter is equal to the ratio of their corresponding sides.

$\therefore \frac{perimeterABC}{perimeterLMN}=\frac{AB}{LM}$

$\Rightarrow \frac{60}{48}=\frac{AB}{8}$

$\Rightarrow AB=\frac{60\times 8}{48}=10cm$